W = Work done ; F = Force = mg ; S = Displacement = 2 m; θ = Angle = 0° ↠ W = 25 × 9.8 × 2 × cos0° ↠ W = 490 × 1. ↠ W = 490. Hence, When a body carried to the same place by pushing it up an inclined plane making an angle of 0° with the ground then work done will be 490 J. Calculate the work done. Calculate the work done by a bricklayer who lifted a cement block of mass 10 kg from the floor to a height of 2.5 m (acceleration due to gravity is 9.8 m/s). A force of 297.0 N is used to push a 165 kg mass 30.0 m horizontally in 3.00 s. a. Calculate the work done on the mass. b. Calculate the power developed. In classical mechanics, kinetic energy (KE) is equal to half of an object's mass (1/2*m) multiplied by the velocity squared. For example, if a an object with a mass of 10 kg (m = 10 kg) is moving at a velocity of 5 meters per second (v = 5 m/s), the kinetic energy is equal to 125 Joules, or (1/2 * 10 kg) * 5 m/s 2. Potential Energy Kinetic Energy Mechanical Energy Power In a previous part of Lesson 1, work was described as taking place when a force acts upon an object to cause a displacement. When a force acts to cause an object to be displaced, three quantities must be known in order to calculate the work. Physics Secondary School verified answered • expert verified Find the work done when a 25 kg weight is (1)lifted to a vertical height of 2.0 m from the ground (2) carried to the same place by pushing it up an inclined plane making an angle of 30 degree with the ground . Tanya159 is waiting for your help. Add your answer and earn points. plus Calculate the work done. Solution: Use WD = F x d d = 0 because the boulder does not move = 2000 x 0 so WD = 0 If an object does not move when the force is applied then no work is done. Work is only done if the object moves. Gravitational Potential Energy Whenever we lift up an object we are providing a force to act against gravity. let's calculate work done when things are dropped or lifted let's solve two problems on this here's the first one a dumbbell of mass 5 kilogram drops to the ground from a height of 10 meters calculate the work done by gravity we're given G is 10 meters per second square so let's quickly go ahead and draw the situation so we have a dumbbell If a person (mass = 60 kg) stands 3 ; A 25 kg box is dragged across a floor by a rope that makes an angle of 60 degrees with the horizontal. The tension in the rope is 100 N while the box is dragged 15 m. A) How much work is done by tens; One end of a 6 m long rope is tied to the ceiling. A small rock with mass 0.5 kg is tied to the other end Work and Energy. A. Work is a form of energy. C. Units of work would be equivalent to a Newton times a meter. D. A kg•m2/s2 would be a unit of work. H. A force is applied by a chain to a roller coaster car to carry it up the hill of the first drop of the Shockwave ride. This is an example of work being done. I. Find the work done by the force {eq}\vec{FP} {/eq} on the cart if the ramp is 6.5 m long. The force of friction between the cart and the floor is 10 N. Calculate the weight of the cart. What is the to; A horizontal force F of magnitude 60 N is applied to a 25-kg cart as the cart slides a distance 180 m up a frictionless ramp at angle 9uY5q.